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Q.

If  cos−1xa+cos−1yb=5π12and sin−1xa−sin−1yb=π12  thenx2a2+y2b2=

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a

1

b

14

c

34

d

54

answer is D.

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Detailed Solution

cos−1xa+cos−1yb=5π12………(1)cos−1yb−cos−1xa=π12……..(2)(1)+(2)⇒cos−1yb=π4⇒yb=12(1)−(2)⇒cos−1xa=π6⇒xa=32∴x2a2+y2b2=54
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