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Questions  

If  cos1xa+cos1yb=5π12and sin1xasin1yb=π12  thenx2a2+y2b2=

a
1
b
14
c
34
d
54

detailed solution

Correct option is D

cos−1xa+cos−1yb=5π12………(1)cos−1yb−cos−1xa=π12……..(2)(1)+(2)⇒cos−1yb=π4⇒yb=12(1)−(2)⇒cos−1xa=π6⇒xa=32∴x2a2+y2b2=54

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