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If cosx+cosy+cosα=0 and sinx+siny+sinα=0 then cotx+y2 is equal to

a
sin α
b
cos α
c
cot α
d
sin⁡x+y2

detailed solution

Correct option is C

Given equations may be written ascos⁡x+cos⁡y=−cos⁡α and  sin⁡x+sin⁡y=−sin⁡α⇒ 2cos⁡x+y2cos⁡x−y2=−cos⁡α----i and  2sin⁡x+y2cos⁡x−y2=−sin⁡α----iiFrom Eqs. (i) and (ii), we get2cos⁡x+y2cos⁡x−y22sin⁡x+y2cos⁡x−y2=cos⁡αsin⁡α⇒ cot⁡x+y2=cot⁡α

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