If cosx+cosy+cosα=0 and sinx+siny+sinα=0 then cotx+y2 is equal to
sin α
cos α
cot α
sinx+y2
Given equations may be written as
cosx+cosy=−cosα and sinx+siny=−sinα⇒ 2cosx+y2cosx−y2=−cosα----i and 2sinx+y2cosx−y2=−sinα----ii
From Eqs. (i) and (ii), we get
2cosx+y2cosx−y22sinx+y2cosx−y2=cosαsinα⇒ cotx+y2=cotα