If cos x = tany, cosy = tanz, cosz = tanx, then the value of sinx is
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a
2cos18o
b
cos18o
c
sin18o
d
2sin18o
answer is D.
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Detailed Solution
We have cos x= tany cos2x=tan2y=sec2y−1=cot2z−1 [∵cosy=tanz,secy=cotz]⇒1+cos2x=cot2z=tan2x1−tan2x [∵cosz=tanx]=sin2xcos2x−sin2x⇒ 2sin4x−6sin2x+2=0 or sin2x=3−52=5−122 or sinx=5−12=2sin18∘