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If $\cos (x - y) = a \cos (x + y)$ , then $\cot x \cot y$ is equal to

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a−1a+1

a+1a−1

a−1

a+1

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detailed solution

Correct option is B

cos⁡(x−y)cos⁡(x+y)=a⇒cos⁡(x−y)+cos⁡(x+y)cos⁡(x−y)−cos⁡(x+y)=a+1a−1⇒cot⁡xcot⁡y=a+1a−1

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If cos⁡(x−y)=acos⁡(x+y) , then cot⁡x cot⁡y is equal to

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If $\cos (x - y) = a \cos (x + y)$ , then $\cot x \cot y$ is equal to