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Q.

If cos⁡(x−y)cos⁡(x+y)+cos⁡(z+t)cos⁡(z−t)=0,  hen the value of expression tanx tany tanz tant is equal to

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a

1

b

-1

c

2

d

-2

answer is B.

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Detailed Solution

cos⁡(x−y)cos⁡(x+y)+cos⁡(z+t)cos⁡(z−t)=0 or  1+tan⁡xtan⁡y1−tan⁡xtan⁡y+1−tan⁡ztan⁡t1+tan⁡ztan⁡t=0 or  1+tan⁡ztan⁡t+tan⁡xtan⁡y+tan⁡xtan⁡ytan⁡ztan⁡t+1−tan⁡ztan⁡t−tan⁡xtan⁡y+tan⁡xtan⁡ytan⁡ztan⁡t=0  or  tan⁡xtan⁡ytan⁡ztan⁡t=−1
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