If cos(x−y)cos(x+y)+cos(z+t)cos(z−t)=0, hen the value of expression tanx tany tanz tant is equal to
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a
1
b
-1
c
2
d
-2
answer is B.
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Detailed Solution
cos(x−y)cos(x+y)+cos(z+t)cos(z−t)=0 or 1+tanxtany1−tanxtany+1−tanztant1+tanztant=0 or 1+tanztant+tanxtany+tanxtanytanztant+1−tanztant−tanxtany+tanxtanytanztant=0 or tanxtanytanztant=−1