If cot−1nπ>π6,n∈Nthen the maximum value of ‘n’ is
6
7
5
10
cot−1nπ>π6 ⇒nπ<cotπ6 ∵ cot is decreasing ⇒nπ<3
⇒n<π3
⇒n<5.46
Maximum value of ‘n’ is 5.