First slide

Compound angles

Question

If $\cot 20 ° = p$ then $\frac{\tan 160 ° - \tan 110 °}{1 + \tan 160 ° \tan 110 °} = \frac{p^{2} - 1}{λ p} t h e n 1011 λ =$

Easy

Solution

$\frac{- \tan 20 ° + \cot 20 °}{1 + \tan 20 ° \cot 20 °}$
$= \frac{\frac{- 1}{p} + p}{2} = \frac{p^{2} - 1}{2 p}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App