First slide
Introduction to ITF
Question

If [cot1x]+[cos1x]=0 where  x is non – negative real number and [.] denotes the greatest integer function, then complete set of value of  x is

Difficult
Solution

0<cot1x<π   and 0cos1xπ

and [cot1x]+[cos1x]=0[cot1x]=0 and [cos1x]=0  0cot1x<1 and 0cos1x<1 

cot1<x<    and cos1x1

x(cot1,1]    cos1<cot1

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