If cot2x=cot(x−y)cot(x−z) then cot 2xis equal to (where x≠±π/4)
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a
12(tany+tanz)
b
12(coty+cotz)
c
12(siny+sinz)
d
none of these
answer is B.
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Detailed Solution
cot2x=cot(x−y)cot(x−z) or cot2x=cotxcoty+1coty−cotxcotxcotz+1cotz−cotx or cot2xcotycotz−cot3xcoty−cot3xcotz+cot4x =cot2xcotycotz+cotxcoty+cotxcotz+1 or cot3x(coty+cotz)+cotx(coty+cotz)+1−cot4x=0 or cotx(coty+cotz)1+cot2x+1−cot2x1+cot2x=0 or cotx(coty+cotz)+1−cot2x=0 or cot2x−12cotx=12(coty+cotz)