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If cot2x=cot(xy)cot(xz) ,then cot2x is equal to (where x±π/4

a
12(tan⁡y+tan⁡z)
b
12(cot⁡y+cot⁡z)
c
12(sin⁡y+sin⁡z)
d
none of these

detailed solution

Correct option is B

cot2⁡x=cot⁡(x−y)cot⁡(x−z)or cot2⁡x=cot⁡xcot⁡y+1cot⁡y−cot⁡xcot⁡xcot⁡z+1cot⁡z−cot⁡xor  cot2⁡xcot⁡ycot⁡z−cot3⁡xcot⁡y−cot3⁡xcot⁡z+cot4⁡x =cot2⁡xcot⁡ycot⁡z+cot⁡xcot⁡y+cot⁡xcot⁡z+1or  cot3⁡x(cot⁡y+cot⁡z)+cot⁡x(cot⁡y+cot⁡z)+1−cot4⁡x=0or  cot⁡x(cot⁡y+cot⁡z)1+cot2⁡x+1−cot2⁡x1+cot2⁡x=0or  cot⁡x(cot⁡y+cot⁡z)+1−cot2⁡x=0or  cot2⁡x−12cot⁡x=12(cot⁡y+cot⁡z)

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