If $\int \frac{\sqrt{\cot \mathrm{x}}}{\sin \mathrm{xcos}\mathrm{x}}\mathrm{dx}=\mathrm{P}\sqrt{\cot \mathrm{x}}+\mathrm{Q}$ then the value of P⁴ is

$\begin{array}{l}\text{ Let }\mathrm{I}=\int \frac{\sqrt{\cot \mathrm{x}}}{\sin \mathrm{xcos}\mathrm{x}}\mathrm{dx}=\int \frac{\sqrt{\cot \mathrm{x}}}{\tan \mathrm{x}}{\sec }^2\mathrm{xdx}\\ =\int \frac{{\sec }^2\mathrm{x}}{(\tan \mathrm{x}{)}^{3/2}}\mathrm{dx}=\frac{-2}{\sqrt{\tan \mathrm{x}}}+\mathrm{Q}=-2\sqrt{\cot \mathrm{x}}+\mathrm{Q}\\ \therefore \mathrm{P}=-2\Rightarrow {\mathrm{P}}^4=16\end{array}$