Q.

If ω ≠1is a cube root of unity and (1+ω)2017=A+B(ω) Then A and B are respectively the numbers

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a

0 ,1

b

1 ,1

c

1 ,0

d

-1 , 1

answer is B.

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Detailed Solution

(1+ω)2017=−ω22017=−ω4034=−ω2∴A+Bω=1+ω⇒A=1,B=1
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If ω ≠1is a cube root of unity and (1+ω)2017=A+B(ω) Then A and B are respectively the numbers