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If $ω \neq 1$ is a cube root of unity and $(1 + ω)^{2017} =$ $A + B (ω)$ Then A and B are respectively the numbers

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0 ,1

1 ,1

1 ,0

-1 , 1

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Correct option is B

(1+ω)2017=−ω22017=−ω4034=−ω2∴A+Bω=1+ω⇒A=1,B=1

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If ω ≠1is a cube root of unity and (1+ω)2017=A+B(ω) Then A and B are respectively the numbers

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If $ω \neq 1$ is a cube root of unity and $(1 + ω)^{2017} =$ $A + B (ω)$ Then A and B are respectively the numbers