Q.

If ω ≠ 1 is a cube root of unity, then  11+i+ω2ω21−i−1ω2−1−i−i+ω−1−1 equal

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a

0

b

1

c

i

d

ω

answer is A.

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Detailed Solution

Use R2→R2−R1−R3, then  the first row of the determinant elements are all zero's, hence the determinant value=0
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If ω ≠ 1 is a cube root of unity, then  11+i+ω2ω21−i−1ω2−1−i−i+ω−1−1 equal