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Q.

If ω(≠1) is a cube root of unity, then the value of tan⁡ω2017+ω2225π−π/3

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a

−13

b

13

c

-3

d

3

answer is C.

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Detailed Solution

ω2017=ω3672ω=ωand ω2225=ω3741ω2=ω2∴tan⁡ω2017+ω2225π−π/3=tan⁡ω+ω2π−π/3=tan⁡(−π−π/3)=−tan⁡(π+π/3)=−tan⁡(π/3)=−3

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