If ω(≠1) is a cube root of unity, then the value of tanω2017+ω2225π−π/3
−13
13
-3
3
ω2017=ω3672ω=ω
and ω2225=ω3741ω2=ω2
∴tanω2017+ω2225π−π/3
=tanω+ω2π−π/3
=tan(−π−π/3)=−tan(π+π/3)
=−tan(π/3)=−3