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If $ω (\neq 1)$ is a cube root of unity, then the value of $\tan [(ω^{2017} + ω^{2225}) π - π / 3]$

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detailed solution

Correct option is C

ω2017=ω3672ω=ωand ω2225=ω3741ω2=ω2∴tan⁡ω2017+ω2225π−π/3=tan⁡ω+ω2π−π/3=tan⁡(−π−π/3)=−tan⁡(π+π/3)=−tan⁡(π/3)=−3

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If ω(≠1) is a cube root of unity, then the value of tan⁡ω2017+ω2225π−π/3

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If $ω (\neq 1)$ is a cube root of unity, then the value of $\tan [(ω^{2017} + ω^{2225}) π - π / 3]$