If ω(≠1) is a cube root of unity, then the value  of tan⁡ω2017+ω2225π−π/3

ω2017=ω3672ω=ωand ω2225=ω3741ω2=ω2∴tan⁡ω2017+ω2225π−π/3=tan⁡ω+ω2π−π/3=tan⁡(−π−π/3)=−tan⁡(π+π/3)=−tan⁡(π/3)=−3