First slide
Extreme values and Periodicity of Trigonometric functions
Question

If D=1cosθ1sinθ1cosθ1sinθ1 then D lies in the interval

Moderate
Solution

Expanding D, we get

 D=1+sinθcosθcosθ(sinθcosθ)+sin2θ+1=2+sin2θ+cos2θ=2+2cos(2θπ/4)

As 1cos(2θπ/4)1,22D2+2

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