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Questions  

If D=1cosθ1sinθ1cosθ1sinθ1 then D lies in the interval

a
[0, 4]
b
[2, 4]
c
[2−2,2+2]
d
[-2, 2]

detailed solution

Correct option is C

Expanding D, we get D=1+sin⁡θcos⁡θ−cos⁡θ(−sin⁡θ−cos⁡θ)+−sin2⁡θ+1=2+sin⁡2θ+cos⁡2θ=2+2cos⁡(2θ−π/4)As −1≤cos⁡(2θ−π/4)≤1,2−2≤D≤2+2

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