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Q.

If A=diag(1,–1, 2),B=diag(2,  3,–1) then 3A+4B=

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a

diag(11, 9, 2)

b

diag(11, 9, −2)

c

diag(11, −9, 2)

d

diag(11, −9, −2)

answer is A.

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Detailed Solution

3A+4B=[3000−30006]+[800012000−4]                  =diag(11, 9, 2)
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