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Q.

If ∫dx1+ex=x+Klog⁡1+ex+C then K is equal to

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a

1

b

-1

c

2

d

-2

answer is B.

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Detailed Solution

Substituting 1+ex=t we have∫dx1+ex=∫dtt(t−1)=∫1t−1dt−∫dtt=log⁡[t−1]−log⁡t+C=log⁡ex−log⁡1+ex+C=x−log⁡1+ex+C
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