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If dxx4x2=1x+log|f(x)|+C then f(x) is given by

 

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a
x+1x−1
b
x−1x+1
c
x−1x+11/2
d
x−1x+12

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detailed solution

Correct option is C

1x4−x2=1x2(x−1)(x+1)=121x21x−1−1x+1=121x−1−1x−1x2−1x2−1x−1x+1=121x−1−2x2−1x+1∫dxx4−x2=12log⁡|x−1|−log⁡|x+1|+2x+C=1x+log⁡x−1x+11/2+C.


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