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If dydx=xy+2x+3y+6 then y(−1)−e2y(−3)=

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a

e2−1

b

e2+1

c

2e2−1

d

-2e2−1

answer is C.

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Detailed Solution

dydx=(x+3)(y+2)X=x+3, Y=y+2 ⇒dtY=X⋅dXy=eAx22,y=−2+A⋅e(x+3)2/2y(−1)=−2+Ae2y(−3)=−2+Ay−1−e2x−3=2e2−1

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