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$If \frac{d y}{d x} + y \sec x = \tan x then (\sqrt{2} + 1) y (\frac{π}{4}) - y (o) =$

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Correct option is A

I. F=exp⁡∫sec⁡xdx=sec⁡x+tan⁡x y(sec⁡x+tan⁡x)=∫tan⁡x(sec⁡x+tan⁡x)=sec⁡x+tan⁡x−x+cx=π4→(2+1)yπ4=2+1−π4+cx=0→y(0)=1+c⇒(2+1)yπ4−y(0)=2−π4

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If dydx+ysec⁡x=tan⁡x then (2+1)yπ4−y(o)=

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$If \frac{d y}{d x} + y \sec x = \tan x then (\sqrt{2} + 1) y (\frac{π}{4}) - y (o) =$