Q.
If 4 different biscuits are distributed among 3 children then the probability of receiving atleast one biscut by the 1st child is
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a
2434
b
1−2434
c
13
d
12
answer is B.
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Detailed Solution
P(atleast one) = 1− P(none) = 1− 2434 (no biscuit receiving by 1st child)the probability of receiving at least one biscuit by the 1st child is 1−2434
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