If 4 different biscuits are distributed among 3 children then the probability of receiving atleast one biscut by the 1st child is

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2434

1−2434

answer is B.

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Detailed Solution

P(atleast one) = 1− P(none) = 1− 2434 (no biscuit receiving by 1st child)the probability of receiving at least one biscuit by the 1st child is 1−2434

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