If the direction cosines l,m,n of two perpendicular lines are connected by the relations λl+3m−5n=0 and 10l2+m2−5n2=0 then λ5 is
±3
±1
±4
±5
The direction cosines of two lines are related by relations al+bm+cn=0 and ul2+vm2+wn2=0 . If these two lines are perpendicular then the condition is ∑a2v+w=0
Herea=λ,b=3,c=−5,u=10,v=1,w=−5
Hence,
∑a2v+w=0λ2−4+95+2511=0−4λ2+320=0
Therefore, λ=±45⇒λ5=±4