If the distance between the planes x – 2y + z = d and the plane containing the lines  x−12=y−23=z−34 and x−23=y−34=z−45 is 6, then |d| is

Equation of the plane containing the given line is: x−1y−2z−3234345=0x-2y+z=0 Equation of given plane is x−2y+z=d .  Distance between the planes is 6 . ∴|d-0|1+4+1=6⇒|d|=6