if the distances from the origin of the centres of three circles x2+y2+2λix−c2=0(i=1,2,3) are in GP, then the lengths of the tangents drawn to them from any point on the circle x2+y2=c2 are in
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a
A.P.
b
G.P.
c
H.P.
d
none of these
answer is B.
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Detailed Solution
The centres of the given circles are −λi,0(i=1,2,3) The distances from the origin of the centres are λ1,λ2 and λ3. It is given that λ22=λ1λ3Let P(h,k) be any point on the circle x2+y2=c .Then h2+k2=c2Now, Li= Length of the tangent from (h,k) to x2+y2+2λixx−c2=0⇒ Li=h2+k2+2λih−c2⇒Li=c2+2λih−c2 ∵h2+k2=c2⇒Li=2λjh, i=1,2,3. ∴ L22=2λ2h⇒ L22=2hλ1λ3⇒ L22=2λ1h2λ3h=L1L3 ∵λ22=λ1λ3Hence, L1,L2,L3 are in G.P