If 7103 is divided by 25, then the remainder is
20
16
18
15
We have, 7103−7(49)51−7(50−1)51
=7(5051−51C15050+51C25049−…−1) =7(5051−51C15050+51C25049−…)−7+18−18 −7(5051−51C15050+51C25049−…)−25+18 =k+18(say) Q kis divisible by25,
∴ remainder is 18.