Q.

If 7103 is divided by 25, then the remainder is

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a

20

b

16

c

18

d

15

answer is C.

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Detailed Solution

We have, 7103−7(49)51−7(50−1)51 =7(5051−51C15050+51C25049−…−1) =7(5051−51C15050+51C25049−…)−7+18−18 −7(5051−51C15050+51C25049−…)−25+18 =k+18(say) Q kis divisible by25,∴ remainder is 18.
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