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$If \frac{dy}{dx} = y + 3 > 0 and y (0) = 2 then y (\log 2) is$

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Correct option is B

∫dyy+3=∫dx→log(y+3)=x+c y(0)=2 put x=0log⁡5=c→log⁡(y+3)−log⁡5=x→log⁡y+35=xy+35=ex→y=5ex−3y(log⁡2)=5elog⁡2−3=5×2-3=7

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If dydx=y+3>0 and y(0)=2 then y(log⁡2) is

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$If \frac{dy}{dx} = y + 3 > 0 and y (0) = 2 then y (\log 2) is$