If eλ and e−λ are roots of the equation 3x2−(a+b)x+2a=0, a,b,λ∈R,λ≠0, then the least integral value of b is

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answer is 5.

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Detailed Solution

f(x)=3x2−(a+b)x+2a=0 Product of roots =2a3⇒eλ×e−λ=2a3⇒a=32 Sum of roots =a+b3>2⇒b>6−a⇒b>6−32⇒b>92∴ Least value of b is 5

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