If eλ and e−λ are the roots of 3x2−(a+b)x+2a=0,a,b , λ∈R,λ≠0 then least integral value of b is

f(x)=3x2−(a+b)x+2a=0 has roots eλ and e−λ Product of the roots =1⇒ 2a3=1⇒a=32 Now, sum of the roots =eλ+e−λ=a+b3>2⇒ b>6−a⇒ b>6−32⇒b>92 Therefore, least integral value of b is 5 .