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a
21e+log2
b
1e-log2
c
−1e+log2
d
1e+log2
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Correct option is C
I=∫01 e−xdx1+ex=∫01 dxex1+ex Put ex=z or exdx=dz or dx=dzex=dzz∴ I=∫1e dzz2(1+z)=∫1e 11+z−z−1z2dz=log(1+z)−logz−1z1e=log(1+e)−loge−1e−(log2−log1−1)=log(1+e)−1e−log2∴ K=−1e+log2Similar Questions
The area bounded by the curve f(x) = x + sin x and its inverse function between the ordinates x= 0 to x = , is
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