If ex+ef(x)=e, then for f(x)
Domain is (−∞,1)
Range is (−∞,1]
Domain is (−∞,0]
Range is (−∞,0]
Gives ex+ef(x)=e ef(x)=e−ex⇒ f(x)=logee−ex
Domain e−ex>0x<1⇒x∈(−∞,1) Range (−∞,1)