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Q.

If ex+ef(x)=e , then domain of f(x) is

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a

(−∞, 0]

b

[0, 1]

c

(−∞, 1)

d

(1, ∞)

answer is C.

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Detailed Solution

ex+ef(x)=e⇒ef(x)=e−ex f(x)=loge(e−ex) fx is defined if e−ex>0⇒ex

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