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Questions  

If each of the points ( x1 , 4) and (-2,y1) lies on the line joining the points (2,-1) and (5,-3), then the point P(x1 , y1 ) lies on the line 

a
x=3y
b
x=−3y
c
y=2x+1
d
2x+6y+1=0

detailed solution

Correct option is D

The equation of the line joining (2,-1) and (5,-3) is 2x+3y=1Since x1,4 and −2,y1 lie on 2x+3y=1. x1=−11/2 and y1=5/3Clearly, Px1,y1=P(−11/2,5/3) lies on 2x+6y+1=0.

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