Questions
If each side of length a of an equilateral triangle subtends an angle of at the top of a tower h meter high situated at the center of the triangle, then
detailed solution
Correct option is B
Let O be the center of the equilateral triangle ABC and OP be the tower of height h. Then each of the triangle PAB, PBC and PAC are equilateral and thus PA=PB=AB=a . In triangle ABC,OA is the bisector of the angle A, SoOAa/2=sec300⇒OA=a2.23=a3 Now from right angle triangle POA PA2=OP2+OA2 ⇒a2=h2+a23⇒2a23=h2 ⇒2a2=3h2Talk to our academic expert!
Similar Questions
The angle of elevation of top of an unfinished tower at a point distance 120m from its base is 450. How much height must the tower be raise so that angle of elevation of top at the same point to be 600.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
