If each of the vertices of a triangle has integer: coordinates, then the triangle will not be

Let Ax1,y1, Bx2,y2 and Cx3,y3 be the vertices of a ∆ABC such that xi′s and yi′s are integers. ThenΔ= Area of △ABC= a rational numberBut, if we assume that the triangle is equilateral, thenΔ=34( side )2=34× an integer = a rational number So, the triangle cannot be equilateral