If the eccentric angles of two points P and Q on the ellipse x2a2+y2b2 are α,β such that α+β=π2 then,the locus of the point of intersection of the normals at P and Q is
ax+by=0
ax−by=0
x+y=0
x+y=a+b
Equations of the normal at P and Q are
ax sec α−by cosecα=a2−b2
axsecβ− by cosecβ=a2−b2
If they intersect at (h, k).
ahsecα−bkcosecα=ahcosecα−bksecα
(∵β=π/2−α)
(ah+bk)(secα−cosecα)=0⇒ah+bk=0
Locus of (h,k) is ax+by=0