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Methods of solving first order first degree differential equations

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By Expert Faculty of Sri Chaitanya
Question

 If the eccentricity of curve for which tangent at point P intersects the y axis at M above x-axis such 

 that origin is equidistant from M and point of tangency, is e, then value of 6e2 is  

Difficult
Solution

We have 

OP=OMyxdydx=x2+y2dydx=yx2+y2xdydx=yx1+yx2 putting yx=vdydx=v+xdvdxv+xdvdx=v1+v2logv+1+v2=logcxv+1+v2=cxy+x2+y2=c ⇒curve is parabola  e=1


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 A solution curve of the differential equation x2+xy+4x+2y+4dydx-y2=0,x>0, passes through the point 1,3. Then the solution curve is

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