If the eccentricity of the ellipse x2a2+1+y2a2+2=1 is 1/6 , then the latus rectum of the ellipse is

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106

None of these

answer is B.

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Detailed Solution

Here, a2+2>a2+1 or a2+1=a2+21−e2 or a2+1=a2+256 or 6a2+6=5a2+10 or a2=10−6=4 or a=±2 Latus rectum =2a2+1a2+2=2×56=106

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