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 If the eccentricity of the ellipse x2a2+1+y2a2+2=1 is 1/6 , then the latus rectum of the ellipse is 

a
56
b
106
c
86
d
None of these

detailed solution

Correct option is B

Here, a2+2>a2+1 or     a2+1=a2+21−e2 or     a2+1=a2+256 or  6a2+6=5a2+10 or  a2=10−6=4 or  a=±2 Latus rectum =2a2+1a2+2=2×56=106

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