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If eight persons are to address a meeting then the number of ways in which a specified speaker is to speak before another specified speaker, is

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a
40320
b
2520
c
20160
d
None of these

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detailed solution

Correct option is C

Let A, B be the corresponding speakers. Without any restriction the eight persons can be arranged among themselves in 8! ways, but the number of ways in which A speaks before B and the number of ways in which B speaks before A make up 8!. Also number of ways in which A speaks before B is exactly same as the number of ways in which B speaks before A.∴ the required number of ways =12(8!)=20160.


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