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Q.

If 3% of electric bulbs manufacturing by a company are defective, the probability that a sample of 100 bulbs has no defective ones is

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a

0

b

e−3

c

1−e−3

d

3−e−3

answer is B.

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Detailed Solution

λ=3 (given) ,r=0P(X=0)=e−3300!=e−3    since pX=r=e-λλrr!
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