First slide
Equation of line in Straight lines
Question

If the equal sides AB and AC (each equal to a) of a right angled isosceles triangle ABC be produced to P and Q so that BP×CQ=AB2, then the line PQ always passes through the fixed point

Moderate
Solution

We take A as the origin and AB and AC as x-axis and y-axis respectively.

Let AP = h, AQ = k. 

Equation of the line PQ is

xh+yk=1             ------(1)

Given, BP×CQ=AB2

h-ak-a=a2

hk-ak-ah+a2=a2 or  ak + ha = hk

or ah+ak=1           ------(2)

From (2), it follows that line (1) i.e., PQ passes through the fixed point (a, a)

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