If the equation of the ellipse is 3x2 +2y2 + 6x- 8y+ 5 = 0, then which of the following is/are true?

3x2+2y2+6x−8y+5=0 or (x+1)22+(y−2)23=1Therefore, the center is (-1,2) and the ellipse is vertical (since b>a).a2=2,b2=3  Now, 2=31−e2 or e=13The foci are (−1,2±be) and (−1,2±1) i.e., (-1, 3) and (-1, 1). The directrices are y=2±b/e or y = 5 and y =  -1.