Questions
If the equation of the locus point equidistant from the points and is then the value of c is
a
a12−a22−b22
b
a12+b22−a22−b22
c
12a12+a22+b12+b32
d
12a22+b22−a12−b12
detailed solution
Correct option is D
Let h,k be the points on the locus. Then by the given conditions,h−a2+k−b12=h−a22+k−b22or 2ha1−a2+2kb1−b2+a22+b22−a12−b12=0or 2ha1−a2+kb1−b2+12a22+b22−a12−b12=0 …(1)Also since h,k lies on the given locus, we have a1−a2h+bb1−b2k+c=0 …(2)Comparing (1) and (2) , we get c=12a22+b22−a12−b12Talk to our academic expert!
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