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If the equation of the plane passing through the line of intersection of the planes $ax+by+cz+d=0,{a}_{1}x+{b}_{1}y+{c}_{1}z+{d}_{1}=0$ and perpendicular to the XY-plane is $px+qy+rz+s=0$ then S=

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a

dc1−d1c

b

dc1+d1c

c

dd1+cc1

d

aa1+bb1+cc1

detailed solution

Correct option is A

The plane equation is (ax + by + cz + d) - cc1 (a1x+b1y+c1z+d1)=0

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