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Q.

If the equation of the plane passing through the mirror image of a point2,3,1 with respect to the line x+12=y−31=z+2−1 and containing the line x−23=1−y2=z+11is αx+βy+γz=24then  α+β+γis equal to

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a

21

b

18

c

19

d

20

answer is C.

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Detailed Solution

Suppose that the given point is P2,3,1Given line is L1≅x+12=y−31=z+2−1,General point on the line is R2k−1,k+3,−k−2Direection ratios of PR are 2k−3,k,−k−3PR  is perpendicular to the line L1it gives 22k−3+1k−1−k−3=0⇒k=12R0,72,−52,Hence, Q−2,4,−6 is image of PEquation of the plane passing through the point ,Q−2,4,−6  and the line L2x−2y−1z+13−214−35=0⇒7x+11y+z=24
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