Q.
If the equation x2+2|a|x+4=0 has integral roots, then minimum value of a is
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a
4
b
-52
c
0
d
-4
answer is B.
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Detailed Solution
Let α,β be the roots of the given equation. Clearly α,β<0⇒ α+β=−2|a| and αβ=4 Since α,β <0 and product is 4 possible values of (α,β) are (−1,−4) and -2,-2⇒−2|a|=−5 or −2|a|=−4a=52 or a=2a=±52 or ±2 Hence, the minimum value of a is −52
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