If the equations 2ax2−3bx+4c=0 and 3x2−4x+5=0 have a common root, then (a+b)/(b+c) is equal to (a,b,c∈R)

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335

3431

2931

answer is C.

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Detailed Solution

Since, the second equation has imaginary roots. ∴ 2a3=−3b−4=4c5=k⇒ a=3k2,b=4k3,c=5k4∴ a+bb+c=3k2+4k34k3+5k4=3431

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