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If the equations x2+mx+1=0 and (b−c)x2+(c−a)x+(a−b)=0 have a common root, then

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a

m=-2

b

m=-1

c

m=0

d

m=1

answer is A.

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Detailed Solution

As x=1 satisfies(b−c)x2+(c−a)x+(a−b)=0x=1 must satisfy x2+mx+1=0⇒1+m+1=0⇒m=−2

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