If the equations x2+mx+1=0 and (b−c)x2+(c−a)x+(a−b)=0 have a common root, then
m=-2
m=-1
m=0
m=1
As x=1 satisfies(b−c)x2+(c−a)x+(a−b)=0x=1 must satisfy x2+mx+1=0⇒1+m+1=0⇒m=−2