If (2, 3) is an extremity of a diameter of the circle x2+y2−5x−8y+21=0, then the other extremity of the diameter is

Given Circle is x2+y2−5x−8y+21=0 Center (52,4) Given A(2,3)  one end point of diameter.Let B(a,b)  be the other end point of diameter.∴  Centre =  Mid point of AB⇒(52,4)=(2+a2,3+b2) (∵if  A(x1,y1)B(x2,y2)   then   Mid   Point   of  AB=(x1+x2)2,(y1+y2)2) ⇒52=2+a2,  4=3+b2 ⇒a=3,    ⇒b=5 ∴B(a,b)=(3,5)  is the other end point of diameter