Questions
If , for all x, where and are fixed positive real numbers, then is equal to
detailed solution
Correct option is A
Given f a + b + 1 − x = f xit implies that fx+1=fa+b−xI=1a+b∫abxfx+fx+1dx. .......1⇒I=1a+b∫aba+b−xfx+1+fxdx. .....2Adding (1) and (2) 2I=∫abfx+fx+1dx⇒2I=∫abfa+b−xdx+∫abfx+1dx⇒2I=2∫abfx+1dx⇒I=∫abfx+1dx =∫a+1b+1fxdxSimilar Questions
The value of is
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