If f(α, β)=cosα−sinα1sinαcosα1cos(α+β)−sin(α+β)1, then
f(300, 200) = f(400, 200)
f(200, 400) = f(200, 600)
f(100, 200) = f(200, 200)
none of these
cosα−sinα1sinαcosα1cos(α+β)−sin(α+β)1
=cosα−sinα1sinαcosα1001+sinβ−cosβ [Applying R3→R3−R1(cosβ)+R2(sinβ)]
=(1+sinβ−cosβ)cos2α+sin2α =1+sinβ−cosβ, which is independent of α.